Andrey Rublev, Alexander Zverev crash out in Rotterdam

Rotterdam: Fifth-ranked Andrey Rublev and former world number two Alexander Zverev both crashed out of the Rotterdam ATP event on Wednesday. Second seed Rublev went down 6-4, 6-4 to Australia’s Alex De Minaur who goes on to face American serve-and-volleyer Maxime Cressy for a quarter-final place. Rublev was the second seeded player to exit on Wednesday after Polish world number 10 and fifth seed Hubert Hurkacz lost to Bulgaria’s Grigor Dimitrov 7-6 (7/4), 7-6 (7/5) in the last 16. Zverev, now ranked 17 in the world and attempting to rebuild his career after suffering ankle ligament damage at the French Open last year, slipped to a second round 4-6, 6-3, 6-4 defeat to Dutch player Tallon Griekspoor. Jannik Sinner, fresh from lifting the Montpellier title last weekend, set-up an intriguing last-16 showdown with top seed Stefanos Tsitsipas by seeing off France’s Benjamin Bonzi 6-2, 3-6, 6-1. Fourth seed Holger Rune knocked out French qualifier Constant Lestienne 6-4, 6-4. “It was tricky. It’s a lot about finding the rhythm here in the beginning of the tournament and first match you have to really be on your toes,” said the young Dane. Three-time major winner Stan Wawrinka made the last-eight by seeing off fellow former top 10 rival Richard Gasquet 6-3, 6-3. The Swiss veteran won the tournament in 2015 and advanced to the final in 2019. Read all the Latest News , Trending News ,  Cricket News , Bollywood News ,  India News and Entertainment News here. Follow us on Facebook, Twitter and Instagram.