First woman makes her way into FBI's most-wanted list

Washington: The FBI has put a woman on its most wanted terrorist list for the first time, announcing a reward of $ 1 million for information leading to her arrest. Joanne Chesimard, a member of the extremist group Black Liberation Army, was convicted of killing a New Jersey state trooper 40 years ago during a routine traffic stop. She has been on the run since 1979 when she escaped from prison in Clinton, New Jersey, where she was serving a life term for murder. [caption id=“attachment_748895” align=“alignleft” width=“380”]  Pictures of Joanna Chesimard released by FBI. AFP.[/caption] The state has added its own $ 1 million on top of the million dollars already offered by the FBI for her capture. The FBI said yesterday that on May 2, 1973, Chesimard and two accomplices were stopped for a motor vehicle violation on the New Jersey Turnpike by two troopers with the state police. At the time, Chesimard was wanted for her involvement in several felonies, including bank robbery. Chesimard and her accomplices opened fire on the troopers. “One trooper was wounded and the other was shot and killed execution-style at point-blank range. Chesimard fled the scene, but was subsequently apprehended. One of her accomplices was killed in the shoot-out and the other was also apprehended and remains in jail,” the FBI said. Four years later, Chesimard was found guilty of first degree murder, assault and battery of a police officer, assault with a dangerous weapon, assault with intent to kill, illegal possession of a weapon, and armed robbery. She was sentenced to life in prison. On November 2, 1979, Chesimard escaped from prison and lived underground before being located to Cuba in 1984. Among others listed in this most wanted terrorists list include the Tehrik-e-Taliban Pakistan (TTP) leader Hakimullah Mehsud. PTI